#include <stdio.h>

int main()
{
    int i;
    for(i = 0;;i++)
    if(((i * 8 + 7) * 8 + 1) * 8 + 1 == (34 * i + 15)* 17 + 4)
    {
        printf("The required number is : %d\n",(34 * i + 15) * 17 + 4);
        break; 
    }  
}
   